Question

please simplify it .

Answer 1

sorry for photo quality

Answer 2

$\frac{1}{a - 3} - \frac{1}{a + 3} - \frac{6}{ 9 - {a}^{2} } \\ = \frac{(a + 3) - (a - 3)}{(a - 3)(a + 3)} - \frac{6}{ - ( {a}^{2} - 9) } \\ = \frac{a + 3 - a + 3}{ {a}^{2} - 9 } + \frac{6}{ {a}^{2} - 9 } \\ = \frac{6}{ {a}^{2} - 9} + \frac{6}{ {a}^{2} - 9 } \\ = \frac{12}{ {a}^{2} - 9}$
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