PLEASE SLOVE 20 AND 21 SUMS.
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Step-by-step explanation:
For question 20 use this formula
Perimeter of triangle 1/ perimeter of triangle 2 = side of triangle 1/ side of triangle 2
Let side of triangle 2 be x.
25/15=9/x
X=9*15/25
x=27/5
x=5.4 cm
For question 21 use formula
Area of triangleABC/ Area of triangle DEF = BC^2/ EF^2
Let area of triangle DEF be x cm^2
54/x= 3×3 / 4×4
54/x=9/16
×=54*16/9
x=6*16=96cm^2
Hope it helps*_*
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