Question

please slove the question....​

Answer 1

$\frac{ \frac{3}{7} \times z - \frac{1}{2} }{z - \frac{1}{4} } - \frac{3}{14} = \frac{1}{7} \\ \\ \frac{\frac{3z}{7} - \frac{1}{2} }{ \frac{4z - 1}{4} } - \frac{3}{14} = \frac{1}{7} \\ \\ \frac{ \frac{6z - 7}{14} }{ \frac{4z - 1}{4} } - \frac{3}{14} = \frac{1}{7} \\ \\ \frac{4(6z - 7)}{14(4z - 1)} - \frac{3}{14} = \frac{1}{7} \\ \\ \pink{multipluing \: \: \: by \: \: \: 14 \: \: \: both \: \: \: side} \\ \\ \frac{4(6z - 7)}{4z - 1} </p><p> - 3 = 2 \\ \\ \frac{24z - 28}{4z - 1} = 3 + 2 \\ \\ 24z - 28 = 5(4z - 1) \\ \\ 24z - 28 = 20z - 5 \\ \\ 24z - 20z = 28 - 5 \\ \\ 4z = 23 \\ \\ z = \frac{23}{4}$

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