Question

please so nitnth one

9.find value of x​

Answer 1

Answer:

$value \: of \: x \: is \: {130}^{0}$

Step-by-step explanation:

in triangle ABD...

angle A +angle B + angle D = 180

${45}^{0} + {35}^{0} + y = {180}^{0}$

$y = {100}^{0}$

so......

$y + z = {108}^{0} \\ {100}^{0} + z = {180}^{0} \\ z = {80}^{0}$

so in triangle EDC......

angle E + angle D + angleC= 180

$p \: + {80}^{0} + {50}^{0} = {180}^{0} \\ {180}^{0} - {130}^{0} = p \\ p = {50}^{0}$

so angle AEC +angle DEC=180

${50}^{0} + x = 180 \\ x = 130$

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