please Sol the question fast
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Sin 54° = Cos 36° = ( 1/4 ) (√5 + 1)
=> Cos 54° = √( 1 - Sin² 54°) = ( 1/4 ) √[ 10 – 2 √5 ]
=> 1 – 2 Sin² 27° = ( 1/4 ) √[ 10 – 2 √5 ]
=> 2 Sin² 27° = 1/2 [ 1 - ( 1/4 ) √[ 10 – 2 √5 ]
Multiply both the sides by 8 –
=> 16 Sin² 27° = 8 - 2 √[ 10 – 2 √5 ] = [√ ( 5 + √5 ) - √ ( 3 - √5 ) ] ²
=> 4 Sin 27° = √( 5 + √5 ) - √( 3 - √5 ) ......... Proved
(Neglecting – ve value as Sin is + ve.)
Hope it's help you
=> Cos 54° = √( 1 - Sin² 54°) = ( 1/4 ) √[ 10 – 2 √5 ]
=> 1 – 2 Sin² 27° = ( 1/4 ) √[ 10 – 2 √5 ]
=> 2 Sin² 27° = 1/2 [ 1 - ( 1/4 ) √[ 10 – 2 √5 ]
Multiply both the sides by 8 –
=> 16 Sin² 27° = 8 - 2 √[ 10 – 2 √5 ] = [√ ( 5 + √5 ) - √ ( 3 - √5 ) ] ²
=> 4 Sin 27° = √( 5 + √5 ) - √( 3 - √5 ) ......... Proved
(Neglecting – ve value as Sin is + ve.)
Hope it's help you
sonu1234555:
any other method
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