Math, asked by neelamchoudhary40, 9 months ago

please solve (1) 2xsqaure +x +4=0 (by completing of square method)

Answers

Answered by Anonymous

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$\ {2}{x}^{2} + x + 4= 0 ÷ 2$

$\ {x}^{2} + \frac{x}{2} - 2$

$a=x,2ab = \frac{x}{2}$

${x + \frac{1}{4}}^2 - \frac{1}{16} - 2=0$

${ x +\frac{1}{4}}^2 - \frac{36}{16}$

$\sqrt{\frac{33}{16} - \frac{1}{4}$

Hopes

Answered by Anonymous

2x^2+x+4=0÷2

x^2+x/2-2

a=x,2ab= x/2

x+1/4^2-36/16

33/16-1/4

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