Question

please solve 11 number and please help me... ​

Answer 1

$\color{red}\huge{\underline{\underline{GIVEN\dag}}}$

• (x+a) is a factor of $3x^{2}+6ax+5x−8$

$\color{red}\huge{\underline{\underline{SOLUTION\dag}}}$

$\large\bf \: Since \: its \: a \: factor,$

$x + a = 0$

$x+a=0$

$\therefore x = - a$

$\bf Substituting \: in \:equation$

$\implies 3{( - a)}^{2} + 6a( - a) + 5( - a) - 8 = 0$

$\implies 3{ a}^{2} - 6 {a}^{2} - 5 a - 8 = 0$

$\implies -3{ a}^{2} -5 a -8 = 0$

$\implies a(3a+8)-1(3a+8)=$

$\implies (a-1)(3a+8)=0$

$\boxed{\orange{\therefore a=1}}$

$\bf (or)$

$\implies 3a+8=0$

$\implies 3a=-8$

$\boxed{\orange{\therefore a=\frac{-8}{3}}}$

HOPE THAT HELPS!!