Math, asked by rashi02, 1 year ago

please solve 11 question

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Answers

Answered by Varun1870
1

Diagonals of parallelogram bisect each other

5b-4=3b+6

2b=10

b=5

3b-4=2a

3×5-4=2a

11=2a

a=5 1/2


rashi02: thank you
Answered by VemugantiRahul
0
Hi there!
Here's the answer :

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¶¶¶ When Diagonals of quadrilateral bisect each other, the given quadrilateral is said to be a parallelogram


SOLUTION:

As diagonals bisect each other,
5b - 4 = 3b + 6
=> 2b = 10
=> b = 5

Also
3b - 4 = 2a
Substitute b value
=> 3(5) - 4 = 2a
=> 2a = 11
=> a = 11/2 = 5.5

•°•°•°•°•°<><><<><>><><>°•°•°•°•°

Hope it helps
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