please solve 11 question
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Diagonals of parallelogram bisect each other
5b-4=3b+6
2b=10
b=5
3b-4=2a
3×5-4=2a
11=2a
a=5 1/2
rashi02:
thank you
Answered by
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Hi there!
Here's the answer :
•°•°•°•°•°<><><<><>><><>°•°•°•°•°
¶¶¶ When Diagonals of quadrilateral bisect each other, the given quadrilateral is said to be a parallelogram
SOLUTION:
As diagonals bisect each other,
5b - 4 = 3b + 6
=> 2b = 10
=> b = 5
Also
3b - 4 = 2a
Substitute b value
=> 3(5) - 4 = 2a
=> 2a = 11
=> a = 11/2 = 5.5
•°•°•°•°•°<><><<><>><><>°•°•°•°•°
Hope it helps
Here's the answer :
•°•°•°•°•°<><><<><>><><>°•°•°•°•°
¶¶¶ When Diagonals of quadrilateral bisect each other, the given quadrilateral is said to be a parallelogram
SOLUTION:
As diagonals bisect each other,
5b - 4 = 3b + 6
=> 2b = 10
=> b = 5
Also
3b - 4 = 2a
Substitute b value
=> 3(5) - 4 = 2a
=> 2a = 11
=> a = 11/2 = 5.5
•°•°•°•°•°<><><<><>><><>°•°•°•°•°
Hope it helps
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