please solve 19 one
Attachments:

Answers
Answered by
1
Answer:
Step-by-step explanation:
Attachments:

Answered by
1
let us draw a perpendicular OV on chord ST. It will bisect the chord ST
ST = ST
In OVS
OV/OS = Cos 60°
OV/12 = 1/12
2 OV = 12
OV = 12 /2
OV = 6 Cm
In SOV
SV/SO = Sin 60°
SV /12 = ✔3/2
2 SV = 12✔3
SV = 12✔3 / 2
SV = 6✔3cm
ST = 2 SV
= 2 × 6✔3 CM
=12✔3 CM
Area of OST = 1/2 × ST × OV
= 1/2 × 12✔3 × 6
= 36✔3
= 36 × 1.73
= 62.28 cm ^2
area of sector OSUT = Teta / 360 × pie (r) ^2
= 120 / 360 × 3.14 × 12 ×12
= 3.14 × 4 × 12
= 150.72 cm^2
ST = ST
In OVS
OV/OS = Cos 60°
OV/12 = 1/12
2 OV = 12
OV = 12 /2
OV = 6 Cm
In SOV
SV/SO = Sin 60°
SV /12 = ✔3/2
2 SV = 12✔3
SV = 12✔3 / 2
SV = 6✔3cm
ST = 2 SV
= 2 × 6✔3 CM
=12✔3 CM
Area of OST = 1/2 × ST × OV
= 1/2 × 12✔3 × 6
= 36✔3
= 36 × 1.73
= 62.28 cm ^2
area of sector OSUT = Teta / 360 × pie (r) ^2
= 120 / 360 × 3.14 × 12 ×12
= 3.14 × 4 × 12
= 150.72 cm^2
Similar questions