Question

please solve 1st question

Answer 1

For the Triangle ABC, By using Basic Proportionality Theorem,

DE is parallel to BC.

$\frac{AD}{DB} =\frac{AE}{EC}$

AC=18$</p><p>AC=AE+EC=18$

Consider AE=x

EC=18-x

Thus

$\frac{AD}{DB} =\frac{AE}{EC}$ implies $\frac{2}{3} =\frac{x}{18-x} Now Cross multiplying, we get 2(18-x)=3x 36-2x=3x 36=3x+2x 36=5x 36/5=x$

Thus AE=36/5