please solve 23rd question
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since x-1 and x+3 are factors, so
f(1)=0; f (-3)=0
now,
f (1)=b-a-12
so, b-a-12=0
b-a=12 (1)
also, f (3) = -9a+b+12
so, -9a+b+12=0
9a-b=12 (2)
(1) +(2)
8a=24
a=3
subsituting in (1)
b-3=12
b=15
if u have any other doubts don't hesitate to ask
regards
nimit sharma
f(1)=0; f (-3)=0
now,
f (1)=b-a-12
so, b-a-12=0
b-a=12 (1)
also, f (3) = -9a+b+12
so, -9a+b+12=0
9a-b=12 (2)
(1) +(2)
8a=24
a=3
subsituting in (1)
b-3=12
b=15
if u have any other doubts don't hesitate to ask
regards
nimit sharma
nimbus:
welcome bro
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