Question

please solve.........​

Answer 1

Use the formula

(a+b)^2

${x}^{2} + { \frac{1}{x} }^{2} = {(a + b)}^{2} \\ = {(x + \frac{1}{x}) }^{2} = {x}^{2} + \frac{( {1})^{2} }{(x)} + 2 \times( x) \times \frac{1}{x} \\ it \: is \: given \: that \: the \: value \: ofx + \frac{1}{x} \: is \: 5 \\ use \: te \: identity \: to \: solve \\ = {(5)}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } + 2 \\ 25 - 2 = {x }^{2} + \frac{1}{ {x}^{2} } \\ 23 = {x + \frac{1}{ {x}^{2} } }$

Hope you can now understand... :)

Answer 2

Answer:

Thanks for following...

Myself Hrutuja