Question

please solve 3rd , 4th , 5th questions

Answer 1

Seems like a lot of homework

3.
Area of trapezium =

1/2 x (sum of parallel sides) x altitude

Let the another side be 'a'

105 = 1/2 x (28 + a) x 5
210 ÷ 5 = 28 + a
42 - 28 = a
a = 14 cm

Hence required another parallel side is 14 cm.

4. UPLOADED PICTURE

5.
Area = 1/2 × height × sum of parallel sides
=1/2 × 1.2 × (1.5 + 2)
= 2.1 m^2
$area = 2.1 {m}^{2}$

Answer 2

hey there

hope my answer helps you

3. Given that ,

area of trapezium = 105 cm²

the parallel side = 28cm

height = 5cm

other parallel side = ? ( x cm)

we know area of a trapezium = 1/2 × h × ( sum of the two parallel sides )

=> 1/2 × 5 × ( 28 + x ) = 105

expanding the brackets

70 + 5x = 105

5x = 105 - 70

5x = 35

x = 7cm