Question

please solve 4 and 5.

Answer 1

the answer of the question is in the picture below

Answer 2

Perimeter of triangle = sum of all sides .
42cm = 18cm+10cm + x cm .
x= 42-28 cm.
x= 14cm.
Area of triangle =
$\sqrt{s(s - a)(s - b)(s - c)}$
s= a+b+c/2 .
s= 42/2 = 21 cm.
$\sqrt{21(21 - 18)(21 - 10)(21 - 14)}$
$\sqrt{21 \times 3 \times 11 \times 7}$
$\sqrt{4851} \: \: \: = \: \: \: \: 21 \sqrt{11 \: \: \ \:} {cm}^{2}$

5) Ratio :- 12:17:25
Let the ratio be 12x , 17x, 25x .
ATQ,
Perimeter of triangle = sum of all sides.
540cm= 12x+17x+25x.
= 54x = 540cm
x= 10cm.
it's side = 120cm , 170cm , 250cm.
$area \: of \: triangle \: = \: \: \sqrt{s(s - a)(s - b)(s - c)}$
s= 540/2 cm = 270 cm
$\sqrt{270(270 - 120)(270 - 170)(270 - 250)}$
$\sqrt{270 \times 150 \times 100 \times 20 \ \: } {cm}^{2} \: \: \: \: = \: \: 9000 {cm}^{2}$
Hope this answer will help you and plz mark it as brainliest.