Please Solve 6 th sum. urgent
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(6):area of trapezium = 1/2 (sum of // sides ) × distance between them .
let other side be x
1/2 (80+x) ×4 = 256
80+x = 128
x = 48 m..
mark brainliest only if you like answer.☺
(3): area of rhombus = 1/2 (d1×d2)
let their ration be x
then they lengths are 5x and 4x m.
1/2 (5x×4x) = 2250
20x^2 = 4500
x^2 = 225
x = 15 m
then d1 = 15×5 = 75 m .
d2 = 15×4= 60 m....☺
let other side be x
1/2 (80+x) ×4 = 256
80+x = 128
x = 48 m..
mark brainliest only if you like answer.☺
(3): area of rhombus = 1/2 (d1×d2)
let their ration be x
then they lengths are 5x and 4x m.
1/2 (5x×4x) = 2250
20x^2 = 4500
x^2 = 225
x = 15 m
then d1 = 15×5 = 75 m .
d2 = 15×4= 60 m....☺
sahajswag:
but thanks for help
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