please solve....,..........
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jahnvi2005:
please do
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it's the correct answer
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AC=BC
AC+AC=BC+AC
2AC=AB. (1)
Since D is also mid point
AD=DB
AD+AD=DB+AD
2AD=AB. (2)
By (1)&(2)
2AC=2AD
AC=AD
this is possible when D coinsides with C
therefore AC=BD
AC+AC=BC+AC
2AC=AB. (1)
Since D is also mid point
AD=DB
AD+AD=DB+AD
2AD=AB. (2)
By (1)&(2)
2AC=2AD
AC=AD
this is possible when D coinsides with C
therefore AC=BD
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