Question

please solve.................

Answer 1

$\lim_{x \to 2} \frac {\frac{d(x^3 -6x^2 +11x-6)}{dx}}{\frac{d(x^2 -6x+8)}{dx}}\\ \: by \: using \: L'Hopital \:Rule \\ Thus, \lim_{x\to 2}=\boxed{\textcolor{red}{\frac{1}{2}}}$