Physics, asked by Luchingbi, 11 months ago

Please solve 9 and 10...with workout..​

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Answers

Answered by rahulmudam20004
1

Answer:

according to ohm' law V=IR

I=V/R

I =9/12

I = 0.75 Amperes

Answered by Anonymous
7

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1.)Given 

Battery=9V

resistors of 0.2 ohm, 0.3ohm, 0.4ohm, 0.5ohm and 12ohm are connected in series to battery.

R1=0.2ohm

R2=0.3ohm

R3=0.4ohm

R4=0.5ohm

R5=12ohm

As all are connected in series effective resistance would be :

Reff=R1+R2+R3+R4+R5

=0.2+0.3+0.4+0.5+12

=13.4OHMS

By ohms law : V=IR

I=V/R

=9/13.4

=0.67 A

As resistors are connected in series. I=I1=I2=I3=I4=I5

Hence current across 12ohms resistor is 0.67A     

2. )   voltage= 220V

Current = 5A

Resistance= 44ohm

Resistance of 44ohm is required

we know resistance in parallel

if we have same resistors is

R = R'/n

where n is number of resistor used

Here R'= 176ohm and R is 44 ohm

n= R'/R = 176/44= 4

Number of resistors used = 4

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