Please solve 9 and 10...with workout..
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1
Answer:
according to ohm' law V=IR
I=V/R
I =9/12
I = 0.75 Amperes
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1.)Given
Battery=9V
resistors of 0.2 ohm, 0.3ohm, 0.4ohm, 0.5ohm and 12ohm are connected in series to battery.
R1=0.2ohm
R2=0.3ohm
R3=0.4ohm
R4=0.5ohm
R5=12ohm
As all are connected in series effective resistance would be :
Reff=R1+R2+R3+R4+R5
=0.2+0.3+0.4+0.5+12
=13.4OHMS
By ohms law : V=IR
I=V/R
=9/13.4
=0.67 A
As resistors are connected in series. I=I1=I2=I3=I4=I5
Hence current across 12ohms resistor is 0.67A
2. ) voltage= 220V
Current = 5A
Resistance= 44ohm
Resistance of 44ohm is required
we know resistance in parallel
if we have same resistors is
R = R'/n
where n is number of resistor used
Here R'= 176ohm and R is 44 ohm
n= R'/R = 176/44= 4
Number of resistors used = 4
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