Please solve. ...............................
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4(x+3y)² - 28(x+3y) +49
Substituting (x+3y) by m,
4m²-28m+49
4m²-14m-14m+49
2m(2m-7)-7(2m-7)
(2m-7)(2m-7)
resubstituting the value of m by (x+3y)
[2(x+3y) -7 ][2(x+3y) -7 ]
(2x+6y-7)(2x+6y-7)
Answered by
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HEY MATE HERE'S UR ANSWER ❤ ❤ ❤ ❤ ❤ ❤ ❤ ❤ ❤ ❤ ❤ ❤ ❤
4(x+3y)2 − 28(x+3y)+ 49
=[2(x+3y)]2 − 2{2(x+3y)}(7) + (7)2
=[2(x+3y) − 7]2
[as, a2−2ab+b2 = (a−b)2]
=(2x + 6y − 7)2
=(2x + 6y − 7)(2x + 6y − 7)
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