please solve all question
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in Question number 8
assume AB || CD
so angle EGB = angle GHD ( as congruent angles)
angle EGA + EGB = 180
so (2x + 15) + (x + 15) = 180
=> 3x +30 = 180
=> 3x = 150
=> x = 50°
50° is the value of x which will make AB || CD
Question number 9 is done in the same way
in question number 10
Given AB || DE
So
angle "a" = 40°
angle "b" = 55°
(Because of alternate interior opposite angles)
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