Question

please solve all question ​

Answer 1

in Question number 8

assume AB || CD

so angle EGB = angle GHD ( as congruent angles)

angle EGA + EGB = 180

so (2x + 15) + (x + 15) = 180

=> 3x +30 = 180

=> 3x = 150

=> x = 50°

50° is the value of x which will make AB || CD

Question number 9 is done in the same way

in question number 10

Given AB || DE

So

angle "a" = 40°

angle "b" = 55°

(Because of alternate interior opposite angles)