Question

please solve all three questions​

Answer 1

16.

99² = (100-1)²

using (a-b)² = a² + b² - 2ab

where a = 100. and b=1

$= {100}^{2} + {1}^{2} - (2)(100)(1) \\ = 10000 + 1 + - 200 \\ = 10001 - 200 \\ = 9801$

17. image on top...

18.

${3}^{5} \times {3}^{2} \times {3}^{ - 8} \times {3}^{2}$

using

${x}^{m} \times {x}^{n} = {x}^{m + n}$

$then \\ = {3}^{5 + 2 - 8 + 2} \\ = {3}^{1} \\ = 3$

I hope this helps ...

with love,

regards ,

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