Please solve and explain.
Attachments:
Answers
Answered by
1
∆AEC is congruent to ∆CDB
So, AC = BC ↔ a(CAE) = a(ABC)
Also , a(CAE) = a(BCD)
So , a(ABC) = a(CAB) = a(BCA) = 180/3 = 60°
So , ∆ABC is an Equilateral ∆
So, AC = BC ↔ a(CAE) = a(ABC)
Also , a(CAE) = a(BCD)
So , a(ABC) = a(CAB) = a(BCA) = 180/3 = 60°
So , ∆ABC is an Equilateral ∆
Similar questions