Please solve ASAP
A body of mass 10 kg is moving on a rough level plane with a constant speed of
4 ms−1.
(i) How many minimum number of forces are acting on it ? Explain your answer.
(ii) If a force of 20 N is now applied on the body for 2 s in the direction of motion,
calculate its speed after 2 s.
(iii) How much distance will it travel in these two seconds ?
Answers
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minimum number of forces would be 3 . i.e weight of the body , normal reaction , kinetic friction acting due to the roughness of the surface .
if force of 20 N is applied
acceleration is 2 m per second square
v= 4+ 2*2 = 8m/s
now for distance use third equation of motion
64=16+ 2*2*s
s= 12 m
if force of 20 N is applied
acceleration is 2 m per second square
v= 4+ 2*2 = 8m/s
now for distance use third equation of motion
64=16+ 2*2*s
s= 12 m
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