Question

Please solve both questions with full solution​

Answer 1

Verify a × (b + c) = a × b + a × c by taking a = 3/4, b = – 5/6 and c = 2/3.

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Given that :

• a = 3/4
• b = – 5/6
• c = 2/3

Let’s substitute these values and verify :

$\sf:\implies~a \times (b + c) = a \times b + a \times c$

$\sf :\implies~ \dfrac{3}{4} \bigg (\dfrac{-5}{6} + \dfrac{2}{3} \bigg) = \dfrac{3}{4} \bigg(\dfrac{-5}{6} \bigg) + \dfrac{3}{4} \bigg (\dfrac{2}{3} \bigg)$

$\sf:\implies~ \dfrac{3}{4}\bigg(\dfrac{-5+4}{6} \bigg) = \dfrac{-15}{24} + \dfrac{6}{12}$

$\sf :\implies~ \dfrac{3}{4} \bigg(\dfrac{-1}{6}\bigg) =\dfrac {- 15 + 12}{24}$

$\sf :\implies~\dfrac {- 3}{24} =\dfrac {- 3}{24}$

$:\implies~$ LHS = RHS

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➪ Hence, verified!

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Find the value of k, so that (– 2)⁽ᵏ⁺¹⁾ × (– 2)⁽³ᵏ⁻²⁾ = (– 2)⁽⁻⁹⁾.

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Here, the bases are all same, so let’s equate the powers :

$\sf :\implies~ a^{(m )}\times a^{(n)} = a^{(m + n)}$

$\sf :\implies~ (k + 1) + (3k - 2) = - 9$

$\sf :\implies~ k + 1 + 3k - 2 = - 9$

$\sf :\implies~ 4k - 1 = - 9$

$\sf :\implies~ 4k = - 9 + 1$

$\sf :\implies~ 4k = - 8$

$\sf :\implies~ k = \dfrac{-8}{4}$

$\sf :\implies~ k = - 2$

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➪ Therefore, the value of k is – 2.

Answer 2

Answer:

The Answer Is Done By solution I only know how to solve ques 3 sorry I didn't knew how to do ques 4 hope I've done good