Math, asked by neilsylvainefernande, 7 months ago

Please solve both the questions

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Answered by sanandgupta142

0

Answer:

Step-by-step explanation:

devide sine in both numerator & denominator

cote-1+cosece/cote+1-cosece

=cote-1+cosece/cote+1-cosece× cote-cosece/cote-cosece

=cot²e-cosec²e-(cote-cosece)/ (cote-cosece+1)(cote-cosece)

=cot²e-cosec²e-cote+cosece/ (cote-cosece+1)(cote-cosece)

=cot²e-1-cot²e-cote+cosece/ (cote-cosece+1)(cote-cosece)

=-(1+cote-cosece)/ (cote-cosece+1)(cote-cosece)

=-1/-(cosece-cote)

=1/cosece-cote×cosece+cote/cosece+cote

=cosece+cote/cosec²e-cot²e

=cosece+cote [since cosec²e-cot²e=1]

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