please solve chemistry emergency 50 points........
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Sol :- For AgNO3 solution 1 M = 1 N
No. of g.equicavalents of silver in 125ml of 1 N AgNO3 solution
125×1 / 1000 = 0.125 g.equivalents
For the deposting of 1g equivalent of silver 96500C o electric current is required .
:- For the deposition of 0.125 g .eq. of A current required is 95600 × 0.125C
Q = I t 96500 × 0.125 = 241.25 × t
t = 96500 × 0.155 / 241.25 = 50 seconds .
Sol :- For AgNO3 solution 1 M = 1 N
No. of g.equicavalents of silver in 125ml of 1 N AgNO3 solution
125×1 / 1000 = 0.125 g.equivalents
For the deposting of 1g equivalent of silver 96500C o electric current is required .
:- For the deposition of 0.125 g .eq. of A current required is 95600 × 0.125C
Q = I t 96500 × 0.125 = 241.25 × t
t = 96500 × 0.155 / 241.25 = 50 seconds .
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Time taken for depositing all the silver present in 125 ml of 1 m AgNO3 solution by passing a current of 241.25A will be 50 second....
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