Math, asked by muskan10453, 8 days ago

Please solve correctly this equation of both these sides given... in terms of x and y.​

Attachments:

Answers

Answered by shreyas246
1

(x+1)2+(y−5)2=0

Adding −(y−5)2 on both sides:

(x+1)2+(y−5)2−(y−5)2=0−(y−5)2

(x+1)2+0=0−(y−5)2

(x+1)2=−(y−5)2⟶ Equation E

The square of any number is always non-negative. So, we have

(x+1)2≥0

and

(y−5)2≥0

So, the equation E is valid if and only if

(x+1)2=0

and

(y−5)2=0

Solving the equations, we have

(x+1)2=0⟹x+1=0

⟹x=−1

and

(y−5)2=0⟹y−5=0

⟹y=5

So, we have

x+y=y+x=5+(−1)=5−1=4

x+y=4

___________________________________________

♥*♡∞:。.。Answer by Shreyas。.。:∞♡*♥

___________________________________________

Attachments:
Similar questions