Math, asked by jaishankarverma62, 10 months ago

please solve don't post spam

only brainlist student can solve​

Attachments:

Answers

Answered by rishu6845
1

Answer:

1) y² ( x + y - 2 x² z² )

2) 4 p² + 16 q² / 25 - 16 p q / 5

Step-by-step explanation:

Given---> 1) ( x² y - y z² )²

2) ( 2p - 4q / 5 )²

To find ---> Value of given expression

Solution---> We know that,

( a - b )² = a² + b² - 2ab

Now,

1) ( x² y - y z² )²

Applying above identity , we get,

= ( x² y )² + ( y z² )² - 2 ( x² y ) ( y z² )

= ( x² )² ( y )² + ( y )² ( z² )² - 2 x² y¹⁺¹ z²

= x⁴ y² + y² z⁴ - 2 x² y² z²

We can take y² commmon

= y² ( x⁴ + z⁴ - 2 x² z² )

2) ( 2 p - 4 q / 5 )²

Applying above identity , we get,

= ( 2 p )² + ( 4q / 5 )² - 2 ( 2 p ) ( 4q / 5 )

= 4p² + 16 q² / 25 - 16 p q / 5

#Answerwithquality

#BAL

Answered by Anonymous
0

(x²y-yz²)²

= x⁴y²+y²z⁴-2x²y²z²

= y²(x⁴+z⁴-2x²z²)

= y²(x²-z²) ²

(2p-4/5q)²

= 4p²+16/25q²-8/5pq

Please follow me thanks ❤

Similar questions