Question

please solve

explain step by step

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Answer 1

Area of Triangle 1 Divided

Answer 2

$\huge \bf\red{ \mid{ \overline{ \underline{ANSWER}}}\mid}$

$\bf{question = }$

Areas of two similar triangles are 81:10 then the ratio of corresponding sides is


Now

$\bf{solution - }solution−  \sf{given - }$

$\sf{to \: find - }$


the ratio of corresponding sides?


$\bf{ \green{step \: by \: step \: explanation}}$

As we are familiar with a theorem that

let ABC and PQR be two similar triangles.

and

AB is corresponding side of PQ
AC is corresponding side of PR
and
BC is corresponding side of QR

then 
$\frac{ar \triangle{abc}}{ar \triangle{pqr}} = (\frac{ab}{pq} )^{2} = (\frac{ac}{pr}) ^{2} = (\frac{bc}{qr} )^{2}$

we are given the ratio of areas then

$\frac{81}{10} = (\frac{ab}{pq} )^{2}$

so

$\frac{ab}{pq} = \sqrt{ \frac{81}{10} }$

$\frac{ab}{pq} = \frac{9}{2 \sqrt{5} }$

and

we already showed above that ratios of sides are equal


so

answer is

$\bf{ \frac{ab}{pq} = \frac{9}{2 \sqrt{5}}}$



$\huge\bf\pink{THANKS}$