Question

please solve fast.,..................​

Answer 1

Answer:

d) ±3√13

Step-by-step explanation:

given,

$a-\frac{1}{a}=3$

squaring both sides, we get

$(a-\frac{1}{a} )^2=3^2$

$=>a^2+\frac{1}{a^2}-2=9$

adding 4 to both sides, we get

$=>a^2+\frac{1}{a^2}+2=13$

$=>(a+\frac{1}{a} )^2=(\sqrt{13})^2$

$=>(a+\frac{1}{a} )=$±$\sqrt{13}$

so,

$a^2-\frac{1}{a^2}=(a+\frac{1}{a})(a-\frac{1}{a})$

$a^2-\frac{1}{a^2}=$±$\sqrt{13}X3$

$a^2-\frac{1}{a^2}=$±3√13

HOPE IT HELPS,

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