Question

please solve fast

it's urgent. ​

Answer 1

Hey mate here is your answer:

Let the point at a distance of 4 cm be PO

Given:

PA=8 cm and PO=4 cm,

<POA=90°[Line joining centre of circle to a chord are perpendicular bisector]

APPLY PYTHAGORAS THEOREM:

$(8) {}^{2} = (4) {}^{2} + ao$

$= = > 64 - 16 = (ao) {}^{2}$

$ao = \sqrt{48}$

$ao = 4 \sqrt{3cm}$

Now, area of semi circle=

$\frac{1}{2} \times \pi \times r {}^{2}$

$\frac{1}{2} \times 3.14 \times (4 \sqrt{3} ) {}^{2} = area$

$area = 75cm</strong><strong>^</strong><strong>2</strong><strong>$