Question

please solve fast . it's very urgent

Answer 1

1 M HCl = 36.5 g in 1 litre

0.75 M HCl = 27.375 g in 1 litre

For 25 mL = 27.375 x 25 /1000 = 0.68 g HCl

73 g of HCl required to react with 100 gof CaCO3

0.68 g HCl will react with 100 x 0.68 / 73 = 0.93 g CaCO3

Mass of CaCO3 required is 0.93 g