please solve fast please
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◆ Quadratic Resolutions ◆
Hey !!
Check the attachment.
Hope it helps you :)
Hey !!
Check the attachment.
Hope it helps you :)
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Anonymous:
NYC
Thnx :)
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Answered by
15
Heya User,
--> Consider the roots..
Since the ratio is 3 : 2 :-> the roots can be written as :->
--> 3a || 2a
--> We know that sum of roots = - [ co-eff x ] / [ coeff x² ]
--> and that product of roots = constant term / [ coeff x² ]
Hence,
--> 3a + 2a = -m / 12
=> a = -m / 60
Further,
--> ( 3a )( 2a ) = 5 / 12
=> 6 [ m² / 3600 ] = 5 / 12
=> m² = 250
=> m = 5√10 ^_^ ^_^ ^_^ 0_0 0_0 0_0
=> The option ( i ) is correct
--> Consider the roots..
Since the ratio is 3 : 2 :-> the roots can be written as :->
--> 3a || 2a
--> We know that sum of roots = - [ co-eff x ] / [ coeff x² ]
--> and that product of roots = constant term / [ coeff x² ]
Hence,
--> 3a + 2a = -m / 12
=> a = -m / 60
Further,
--> ( 3a )( 2a ) = 5 / 12
=> 6 [ m² / 3600 ] = 5 / 12
=> m² = 250
=> m = 5√10 ^_^ ^_^ ^_^ 0_0 0_0 0_0
=> The option ( i ) is correct
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