Question

Please solve fast
You are given a and b are rational numbers. If (3-√2)/3+√2=a + b√2, then find the value of a and b

Answer 1

it is given that 3 -√2/(3 + √2)=a+b 
solving 
3-√2/3+√2=3-√2/3+√2 *3-√2/3-√2   in this step we have rationalised by 3-√2
this will give you (3-√2)²/9-2   using (a+b)(a-b)=a²-b²
=9+2-6√2/7
=11=6√2/7
=a=11/7 
b=6/7    by comparing a+b√2 by our ans

sorry it was my mistake it is -6/7 as while comparing a+b√2=11+(-6√2)/7 
once again sorry! so b=-6/7