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You are given a and b are rational numbers. If (3-√2)/3+√2=a + b√2, then find the value of a and b
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it is given that 3 -√2/(3 + √2)=a+b
solving
3-√2/3+√2=3-√2/3+√2 *3-√2/3-√2 in this step we have rationalised by 3-√2
this will give you (3-√2)²/9-2 using (a+b)(a-b)=a²-b²
=9+2-6√2/7
=11=6√2/7
=a=11/7
b=6/7 by comparing a+b√2 by our ans
sorry it was my mistake it is -6/7 as while comparing a+b√2=11+(-6√2)/7
once again sorry! so b=-6/7
solving
3-√2/3+√2=3-√2/3+√2 *3-√2/3-√2 in this step we have rationalised by 3-√2
this will give you (3-√2)²/9-2 using (a+b)(a-b)=a²-b²
=9+2-6√2/7
=11=6√2/7
=a=11/7
b=6/7 by comparing a+b√2 by our ans
sorry it was my mistake it is -6/7 as while comparing a+b√2=11+(-6√2)/7
once again sorry! so b=-6/7
chandraharish:
but the value of b is given -6/7
in case of a doubt reply back
ya in the answer sheet given to us the value of b is -6/7 not 6/7
is it ok now!
ya thanks
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