Question

please solve for the question help!! tomorrow exams​

Answer 1

Step-by-step explanation:

Given=

ā=i+2j+3k ,. b=2i+3j+4k

therefore

place value of a and b in each equation

1. 3a+4b

=3(i+2j+3k)+4(2i+3j+4k)

now multiply

=(3i+6j+9k)+(8i+12j+16k)

=3i+8i+6j+12j +9k+16k

=11i+18j+25k

2.a+2b

=(i+2j+3k)+2(2i+3j+4k)

=(i+2j+3k)+(4i+6j+8k)

=i+4i + 2j+6j + 3k+8k

=5i+8j+11k

3.3a-2b

3a=3(i+2j+3k)=3i+6j+9k

2b=2(2i+3j+4k)=4i+6j+8k

therefore,

3a-2b= (3i+6j+9k)-(4i+6j+8k)

=3i+6j+9k-4i-6j-8k

= -i+k

4.2a-a

2a=2(i+2j+3k)=2i+4j+6k

therefore

2a-a= (2i+4j+6k)-(i+2j+3k)

=2i+4j+6k-i-2j-3k

=I+2j+3k=a

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