Question

please solve
give appropriate answer



uneccessary answers not be avoided❌❌❎❎
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Answer 1

$let \: the \: mass \: of \: compound \: \\ be \: 100 \: gram \\ \\ c = \: 70.6g \: = \frac{70.6}{12}moles = 5.88 \: moles \ \\ \\ h = \: 4.2g \: = \frac{4.2}{1} moles = 4.2 \: moles \\ \\ n = \: 11.8g \: = \frac{11.8}{14} moles =0.84 \: moles \\ \\ o = \: 13.4g \: = \frac{13.4}{16} moles = 0.84 \: moles \\ \\ c.h.n.o = 5.88 .. 4.2.. 0.84 .. 0.84 \\ \\ c.h.n.o = 7..5..1..1 \\ \\ therefore \: empirical \: formula \: \\ of \: kelvar \: is \\ \\ c7h5no \: answer. \\ \\ i \: hope \: that \: is \: helpful \: for \: you.$

Answer 2

Answer:

this is your answer

Explanation:

letthemassofcompound

be100gram

c=70.6g=

12

70.6

moles=5.88moles

h=4.2g=

1

4.2

moles=4.2moles

n=11.8g=

14

11.8

moles=0.84moles

o=13.4g=

16

13.4

moles=0.84mole