Question

Please solve in detail if anybody can do.Do quick not have much time

Answer 1

Answer:

xˣ^² ( x + 2xlogx ) + 2x aˣ^² loga

Step-by-step explanation:

Given----->

y = xˣ^² + aˣ^²

To find ----> dy / dx

Solution-----> 1) Plz see the attachement

2) First we suppose first term and second term as A and B . then we differentiate A and B seperately

3) For differentiation of A , we take log and used , property of log ,

log pⁿ = n logp

4) Then we differentiate by applying product rule

d/dx ( u v ) = u dv/dx + v du/dx

and using two formulee of differentiation

d/dx ( xⁿ ) = n xⁿ⁻¹

d/dx ( logx ) = 1 / x

5) For differentiation of B , we use a formula of differentiation

d/dx ( aˣ ) = aˣ loga

6) Then putting value of dA / dx and dB / dx we get value of dy/dx .