Math, asked by sahil2535, 11 months ago

please solve it,,,,,,​

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Answered by Anonymous
2

Answer:

Number of days = 20 days

Step-by-step explanation:

It is given that, A.B. C can finish one task in 24 days, 32 days and 64 days respectively

To find the LCM of 24,32,and 64

LCM(24,32,64) = 192

To find efficiency of A,B and C

efficiency of A = 192/24 = 8

efficiency of A = 192/32 = 6

efficiency of A = 192/64 = 3

To find the number of days

One day work of A, B and C together = 8+6+3 = 17

6 days they together work, then total work completed after 6 days = 6 * 17 = 102.

Last 6 days C's work  =6*efficiency of C =  6 * 3 = 18

Therefore the 12 days work = 102 + 18 = 120

Then the remaining work = 192 - 120 = 72

This work completed by B and C

Number of days taken by B and C = 72/(efficiency of B and C) = 72/9 = 8 days

Therefore total number of days = 6 + 8 + 6 = 20 days

✴️✴️ may be it's helpful to you ✴️✴️

Answered by Anonymous
1

Answer:

Refer to attachment please

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