please solve it......................
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given here
tan²x + cot²x = 10/7
find here
tan x + cot x= ?
tan x- cot x= ?
Solution :-
we know that
(a+b)²=(a²+b²+2ab)
so
(tan x +cot x)²
= tan²x +cot²x +2tan x cot x
= (10/7)+2×tanx × 1/tan x
= (10/7)+2
= (10+14)/7
= 24/7
tan x + cot x= √(24/7)
(2)
(tan x - cot x )²
= tan ²x + cot²x -2 × tan x × cot x
= tan ²x + cot²x -2
= (10/7)-2
= (10-14)/7
= -4/7
=> tan x - cot x = √(-4/7)
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