Math, asked by rajeevmishra72151, 11 months ago

please solve it......​

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Answers

Answered by ProSaurav
0

Answer:

1) z-4

Step-by-step explanation:

1) z(5z^2-80)÷5z(z+4). {z gets cut}

=5(z^2-16)/5(z+4). {5 taken out common}

=(z^2-4^2)/(z+4). {5 gets cut}

=(z+4)(z-4)/(z+4). {(a+b)(a-b)=a^2-b^2}

=z-4. {(z+4) gets cut}

2) Simplified as,

3(9x^2-16y^2)/(3x+4y)

3(3x+4y)(3x-4y)/(3x-4y)

3(3x+4y)

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