please solve it.................
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Answered by
3
Heya!!!!!
Let the numbers be x,( x+2), (x+4)................
Then,
According to question,
3x-7=2(x+4)
=>3x-7=2x + 8
=>3x-2x=15
=>x= 15.....
Therefore,
Numbers r 15,17,19
Let the numbers be x,( x+2), (x+4)................
Then,
According to question,
3x-7=2(x+4)
=>3x-7=2x + 8
=>3x-2x=15
=>x= 15.....
Therefore,
Numbers r 15,17,19
arya321:
wonderful
Answered by
4
Let the three consecutive integers are x,x+2,x+4.
Given that three times, the smallest of 3 consecutive odd numbers decreased by 7 equals the largest one.
3x - 7 = 2(x + 4)
3x - 7 = 2x + 8
3x - 2x = 7 + 8
x = 15.
Now,
x = 15
x + 2 = 17
x + 4 = 19.
Therefore the numbers are 15,17,19.
Hope this helps!
Given that three times, the smallest of 3 consecutive odd numbers decreased by 7 equals the largest one.
3x - 7 = 2(x + 4)
3x - 7 = 2x + 8
3x - 2x = 7 + 8
x = 15.
Now,
x = 15
x + 2 = 17
x + 4 = 19.
Therefore the numbers are 15,17,19.
Hope this helps!
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