Question

please solve it and help me ​

Answer 1

Answer:

Given,

Radius of a circular tent , R = 30 m

We know, Area of a circle = πR^2

Therefore, Area of a circular tank =

22/7 × ( 30 )^2= 22/7 × 30 × 30= 2828.57 m^2= 2828.6 m^2 ( approx. )

Also, Radius of a circular ring at the center, r = 10 m

We know, Area of the circle =

πr^2= 22/7 × (10)^2= 314.285 m^2

So, Area of the space left for the audience =

πR^2 - πr^2= ( 2826.6 - 314. 285 ) m^2= 2512.315 m^2

Answer 2

Hey mate!
Here's the solution....

Radius of the circustent = 30 m
Area covered by the circus tent $= 2\pi {r}^{2} \\ = 2 \times 3.14 \times 30 \times 30 \\ = 3.14 \times1 800 \: {m}^{2}$

Radius of the circular ring=10 m
Area covered by the ring in the centre $= 2\pi {r}^{2}$

$= 2 \times3.14 \times 10 \times 10$

$= 3.14 \times 200 \: {m}^{2}$

Area left for the audience $= (3.14 \times 1800 - 3.14 \times 200) {m}^{2}$

$= 3.14(1800 - 200) {m}^{2}$

$= 3.14 \times 1600 \: {m}^{2}$

$= 5024 \: {m}^{2}$

I hope it helps you....