Question

Please solve it and I'll mark you brainliest.

Determine the values of the expression below, where the 4 blanks (left to right) represent the following operators:

3_3_3_3_3

Options:
1. +-*/
2.-*/+
3.*/+-
4./+-*

Answer 1

ᴄᴏɴᴄᴇᴘᴛ ᴜsᴇᴅ :-

According to BODMAS Rule,, we have to first solve or simplify Division, Multiplication, Addition and Subtraction from left to right.

Sᴏʟᴜᴛɪᴏɴ :-

1) + - * / = Add, subtract, Multiply , Divide .

So,

→ 3 + 3 - 3 * 3 ÷ 3

Divide First ,

→ 3 + 3 - 3 * (3/3)

→ 3 + 3 - 3 * 1

Multiply Now,

→ 3 + 3 - 3

Add Now,

→ 6 - 3

Subtract Now,

→ 3 (Ans.)

____________________

2) - * / + = Subtract , Multiply, Divide , Add.

→ 3 - 3 * 3 ÷ 3 + 3

Divide First ,

→ 3 - 3 * (3/3) + 3

→ 3 - 3 * 1 + 3

Multiply Now,

→ 3 - 3 + 3

Add Now,

→ 3 - 0

Subtract Now,

→ 3 (Ans.)

_____________________

3) * / + - = Multiply, Divide, Add, Subtract

→ 3 * 3 ÷ 3 + 3 - 3

Divide First ,

→ 3 * (3/3) + 3 - 3

→ 3 * 1 + 3 - 3

Multiply Now,

→ 3 + 3 - 3

Add Now,

→ 6 - 3

Subtract Now,

→ 3 (Ans.)

_____________________

4) / + - * = Divide, Add, Subtract , Multiply.

→ 3 ÷ 3 + 3 - 3 * 3

Divide First ,

→ (3/3) + 3 - 3 * 3

→ 1 + 3 - 3 * 3

Multiply Now,

→ 1 + 3 - 9

Add Now,

→ 4 - 9

Subtract Now,

→ (-5) (Ans.)

_____________________

Answer 2

$\rule{200}2$

$\huge\tt{CONCEPT~USED:}$

• B,O,D,M,A,S for solving
• where, B = Bracket ,O = of , D = Division , M = multiplication, A = Addition , S = Subtraction

$\rule{200}2$

$\huge\tt{SOLUTION:}$

1) Add, Subtract , Multiply , Divide.

⇝3 + 3 - 3 × 3 ÷ 3

⇝3 + 3 - 3 × (3/3)

⇝3 + 3 - 3 × 1

⇝3 + 3 - 3

⇝ 6 - 3

⇝3

2) Subtract, Multiply, Divide, Add

⇝3 - 3 × 3 ÷ 3 + 3

⇝3 - 3 × (3/3) + 3

⇝3 - 3 × 1 + 3

⇝3 - 3 + 3

⇝6 - 3

⇝3

3) Multiply, Divide, add , Subtract

⇝3 × 3 ÷ 3 + 3 3 - 3

⇝3 × (3 /3) + 3 - 3

⇝3 × 1 + 3 - 3

⇝3 + 3 - 3

⇝6 - 3

⇝3

4) Divide , Add , Subtract, Multiply

⇝⇝3 ÷ 3 + 3 - 3 × 3

⇝(3/3) + 3 - 3 × 3

⇝1 + 3 - 3 × 3

⇝1 + 3 - 9

⇝4 - 9

⇝ - 5

$\rule{200}2$