Please Solve it and reply quickly its urgent and you will you get 80 points as reward
Attachments:
Answers
Answered by
1
Answer:
(a- b)x+(a+ b)y=a²-2ab-b²
⇒(a- b)x+(a+ b)y=a²-b² - 2ab
⇒ax- bx+ ay+ by =(a- b)(a + b)-2ab
⇒a(x+y) -b(x-y)=(a-b)(a+b)-2ab
⇒a(a+ b) -b(x-y)=(a- b)(a + b)-2ab [From (i)]
⇒a²+ ab -b(x- y)=a²-b²-2ab
⇒b²+3ab -b(x- y)=0
⇒b(b + 3a) -b(x- y)=0
⇒b[b+3a-x+y]=0
(a+ b)(x+ y)=a² + b²
⇒(a+ b)(x+ y)=(a+ b)(a+ b)
⇒x+ y= a+ b........................(i)
Answered by
0
i will send you the answer via hangouts
Similar questions