Math, asked by chatwithaditi77, 3 months ago

Please solve it and say their ages...​

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Answers

Answered by nada12january
0

Step-by-step explanation:

Let the present age of geeta be ‘x’ years

The present age of Sunita is 2x years geeta

new age = (x – 6) years Sunita’s new age =

 (2x + 4) years

So, (2x + 4) = 4 (x – 6) 2x + 4 =

4x – 24 2x – 4x = -24 – 4 -2x =

-28 x = -

28/-2

= 14 ∴ Age of geeta is x years = 14 years

Age of Sunita is 2x years = 2(14) = 28 years

Two years ago, 

age of geeta is 14 – 2 = 12 years,

age of Sunita = 28 – 2 = 26 years

Answered by unicorn898
0

Answer:

Let Geeta's age = x

Sunita's age = 2x

4 × (x - 6) = 2x + 4

4x - 24 = 2x + 4

4x - 2x = 4 + 24

2x = 28

x = 28/2 = 14

∴ Geeta's age = 14 years

Sunita's age = 2 × 14 = 28 years

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