Please solve it answer is 12cm
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Area of any quadrilateral = 1/2 x diagonal x (sum of perpendicular distances of other vertices to the diagonal)= 1/2 x AC x (DE + BF)
So, we can substitute the values..
Let 'a' be the length of the perpendicular drawn from D on AC.
12×25×(14+a)=325⇒14+a=325×225⇒14+a=26⇒a=26−14⇒a=12 cm
So, we can substitute the values..
Let 'a' be the length of the perpendicular drawn from D on AC.
12×25×(14+a)=325⇒14+a=325×225⇒14+a=26⇒a=26−14⇒a=12 cm
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