Math, asked by shivalipandey904, 9 months ago

please solve it as soon as possible
I need it immediately

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Answered by shardasahil9525
0

2) 6x2-7x-3=0

6x2+2x-9x-3=0

2x(3x+1) -3(3x+1)=0

(3x+1) (2x-3)=0

3x+1=0 2x-3=0

3x=-1 2x=3

x=-1/3 x=3/2

1) firstly, √2 is a irrational no.

let's 5+3√2is a rational number

and,

p&q

5+3√2=p/q [q is not equal to 0]

3√2=p/q-5= p-5q/q

√2= p-5p/3q

p-5q and 3q

now,

5+3√2 is a rational number is wrong

5+3√2is a irrational no.

PROVED

i wish isse apki help hogi

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