Question

Please solve it by Heron's formula​

Answer 1

Answer:

Area = $\dfrac{9\sqrt{195}}{4}$

Step-by-step explanation:

From Heron's formula,

$Area = \sqrt{s(s-a)(s-b)(s-c)}, \text{where s is the semi-perimeter.}\\\\\text{In this case, s =} \dfrac{(7 + 9 + 11)}{2} = \dfrac{27}{2}\\\\Area = \sqrt{\dfrac{27}{2}(\dfrac{27}{2} - 7)(\dfrac{27}{2} - 9)(\dfrac{27}{2} - 11)}\\Area = \sqrt{\dfrac{27}{2} \cdot \dfrac{13}{2} \cdot \dfrac{9}{2} \cdot \dfrac{5}{2}}\\Area = \dfrac{9}{4}\sqrt{195} \text{ sq.cm}$

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