Question

please solve it.... describe the motion of a body which is accelerated at a constant rate of
$10m \: {s}^{ - 2}$
if the body starts from rest how much distance will it cover in 2 second

Answer 1

Use the 1st equation of motion ( v=u+at)
V= 0+ 10×2 [ because it starts from rest initial velocity =0]

V=20m/s



Now use the 3rd equation of motion=(v^2-u^2=2as)

(20^2)-(0^2)=2as
400-0 =2×10×s
400=20×s
400/20=S
20=S

So, distance covered is 20m.

Hope it helps u....
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Answer 2

I don't know very much sorry I also not understand