Question

please solve it fast...​

Answer 1

Explanation:

integration of sec square x

(tanx) limits 0 to π/6

(tanx ) limits 0° to 30°

tan30° - tan0°

√3 - 0

√3

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Answer 2

$\huge \underline{\bf{ {solution}}} : -$

According to the question-

$\implies \: \int\limits_{0}^{ \frac{ \pi}{6} } { \sec}^{2} x.dx \\ \\ \because \: \int\limits_{0}^{ \frac{ \pi}{6} } { \sec }^{2} x. \: dx = \tan(x) \\taking \: limits \: \\ \therefore \: \\ \\ \implies \: \tan( \frac{ \pi}{6} ) - \tan(0) \\ \\ \implies \: \frac{1}{ \sqrt{3} }$